Feb
08
Egyptian Maths
By
Michael S. Schneider explains how the Ancient Egyptians (and Chinese) and modern computers multiply and divide
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25 Comments
February 8th, 2010 at 11:16 pm
Awesome! that was sooo interesting! I’ve been busy practicing this method for like 2 hours now. ^^
February 8th, 2010 at 11:53 pm
can we make (102) square 2 whit this methode
February 9th, 2010 at 12:28 am
binary is base 2. basically it’s 0s and 1s (how computers calculate) but doubling as they go 1, 2, 4, 8, 16. . .
February 9th, 2010 at 12:57 am
you have a remainder of 1 – 1/2, or . 5
February 9th, 2010 at 1:16 am
i have a question, im in the 6th grade and i asked my teacher what binary means, and i really dont know if she ignored me, or didnt hear me but what does it mean. . . .
also i didnt get the part totally where how you find out the product of 7 and 25.
February 9th, 2010 at 2:02 am
what do you do if when dividing, the numbers dont go into each other evenly? (like 275 / 2) ?
February 9th, 2010 at 2:58 am
w o oo oooo oooooooo h hh hhhh ! !!
time to whip out a notebook,
veda sutras math tricks are complex,
THANKS! !! !!!!
February 9th, 2010 at 3:41 am
that’s interesting
February 9th, 2010 at 3:55 am
Molto, molto interessante.
Grazie!
5*
February 9th, 2010 at 4:07 am
xD but mine hurts too and im only 20 and never done drugs T_T xD
February 9th, 2010 at 4:18 am
yeah, that’s cool – it’s great to have the debate and find people interested in maths – to too many it’s just buttons on a calculator
February 9th, 2010 at 4:50 am
Sure, you’re allright. Just wanted to share some cool informations not everybody knows.
February 9th, 2010 at 5:09 am
well perhaps we’re splitting hairs but i think the key word there is ‘denotes’ , because technically it still has to be rounded up.
February 9th, 2010 at 5:51 am
Well, I’m sorry, but in fact 0. 9999r equals exactly 1.
“In mathematics, the repeating decimal 0. 999. . . [. . . ]denotes a real number equal to one. ”
Quoted from wikipedia article “0. 9999″.
Very interesting.
February 9th, 2010 at 6:32 am
it only equals 1 through rounding. 0. 09090909r x 11 = O. 99999999r
February 9th, 2010 at 6:58 am
well nice video but 0. 0909090909 times 11 actually equals 1.
February 9th, 2010 at 7:29 am
part of the problem is that these days, since electronic calculators, people mostly think in decimals, rather than fractions, so people think of . 09090909r rather than 1/11, which to my mind is not necessarily a good thing (although that might be because i’m from a different generation) and certainly not as accurate (because if you add eleven of the decimals you won’t return to one.
haven’t really got the facilities or time to do a video but i will think about it, although not promising.
February 9th, 2010 at 7:47 am
great video! i am still a bit confused on the decimal situation as well. like the instance of 23/11. Can you post another video explaining it? i get the subtracting part but if a computer doesnt use a multiplication table and you end up with a remainder of 1/11 that is where i get lost on how it computes.
thanks.
February 9th, 2010 at 8:09 am
this was great it reminds me of bouline and.
February 9th, 2010 at 8:48 am
my brain hurts. . . . learn math and other languages as young as possible kids. . . oh yea, and don’t do drugs. . .
February 9th, 2010 at 8:53 am
to add, 1/11 in binary would be 1/1011
j
February 9th, 2010 at 9:46 am
well Aron, you’ve got my head working on this one. . .
i think the best way to look at it is to actually convert the numbers to binary – so, 23 = 10111 and 11 = 1011. now if we subtract 1011 from 10111 it leaves us with 1100 (12) now we repeat the process, subtracting 1011 from 1100, leaving us with a remainder of 1, 1/11, or . 0909. . . – does that work for you, or am i just complicating things?
thanks for your interest,
jack
February 9th, 2010 at 10:36 am
Partly, the 1 * 11 and 2 * 11 part but how would the leftover of 1/11:th be described binarily?
February 9th, 2010 at 11:05 am
1 x11 = 11
2 x 11= 22
leaving a remainder of 1, 1/11, or . 0909. . . .
does that explain it?
February 9th, 2010 at 11:44 am
Well I’m thinking like if you divide 23/11, the answer would be 2,09090909090909. . . How is that number explained with binary counting?