Michael S. Schneider explains how the Ancient Egyptians (and Chinese) and modern computers multiply and divide
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Awesome! that was sooo interesting! I’ve been busy practicing this method for like 2 hours now. ^^
can we make (102) square 2 whit this methode
binary is base 2. basically it’s 0s and 1s (how computers calculate) but doubling as they go 1, 2, 4, 8, 16. . .
you have a remainder of 1 – 1/2, or . 5
i have a question, im in the 6th grade and i asked my teacher what binary means, and i really dont know if she ignored me, or didnt hear me but what does it mean. . . .
also i didnt get the part totally where how you find out the product of 7 and 25.
what do you do if when dividing, the numbers dont go into each other evenly? (like 275 / 2) ?
w o oo oooo oooooooo h hh hhhh ! !!
time to whip out a notebook,
veda sutras math tricks are complex,
THANKS! !! !!!!
that’s interesting
Molto, molto interessante.
Grazie!
5*
xD but mine hurts too and im only 20 and never done drugs T_T xD
yeah, that’s cool – it’s great to have the debate and find people interested in maths – to too many it’s just buttons on a calculator
Sure, you’re allright. Just wanted to share some cool informations not everybody knows.
well perhaps we’re splitting hairs but i think the key word there is ‘denotes’ , because technically it still has to be rounded up.
Well, I’m sorry, but in fact 0. 9999r equals exactly 1.
“In mathematics, the repeating decimal 0. 999. . . [. . . ]denotes a real number equal to one. ”
Quoted from wikipedia article “0. 9999″.
Very interesting.
it only equals 1 through rounding. 0. 09090909r x 11 = O. 99999999r
well nice video but 0. 0909090909 times 11 actually equals 1.
part of the problem is that these days, since electronic calculators, people mostly think in decimals, rather than fractions, so people think of . 09090909r rather than 1/11, which to my mind is not necessarily a good thing (although that might be because i’m from a different generation) and certainly not as accurate (because if you add eleven of the decimals you won’t return to one.
haven’t really got the facilities or time to do a video but i will think about it, although not promising.
great video! i am still a bit confused on the decimal situation as well. like the instance of 23/11. Can you post another video explaining it? i get the subtracting part but if a computer doesnt use a multiplication table and you end up with a remainder of 1/11 that is where i get lost on how it computes.
thanks.
this was great it reminds me of bouline and.
my brain hurts. . . . learn math and other languages as young as possible kids. . . oh yea, and don’t do drugs. . .
to add, 1/11 in binary would be 1/1011
j
well Aron, you’ve got my head working on this one. . .
i think the best way to look at it is to actually convert the numbers to binary – so, 23 = 10111 and 11 = 1011. now if we subtract 1011 from 10111 it leaves us with 1100 (12) now we repeat the process, subtracting 1011 from 1100, leaving us with a remainder of 1, 1/11, or . 0909. . . – does that work for you, or am i just complicating things?
thanks for your interest,
jack
Partly, the 1 * 11 and 2 * 11 part but how would the leftover of 1/11:th be described binarily?
1 x11 = 11
2 x 11= 22
leaving a remainder of 1, 1/11, or . 0909. . . .
does that explain it?
Well I’m thinking like if you divide 23/11, the answer would be 2,09090909090909. . . How is that number explained with binary counting?